In the arithmetic sequence 3,7,11, which term is 119? Answer: 119 is the 30th term. Step-by-step explanation: Arithmetic sequence general rule: an = a₁ + (n-1)(d) Where: an = last term ⇒ 119 a₁ = first term ⇒ 3 d = common difference ⇒ (7-3 = 11 - 7) ⇒ 4 n = nth term in the sequence or the number of terms ⇒ unknown Find for what term is 119: an = a₁ + (n-1)(d) 119 = 3 + (n-1)(4) 119 = 3 + 4n - 4 119 = -1 + 4n 4n = 119 + 1 4n/4 = 120/4 n = 30 119 is the 30th term in the given sequence 3, 7, 11, ..., 119.
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